Difference between revisions of "Talk:Optimizing Plugins (AMX Mod X Scripting)"
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Regarding [[User:NiLuJe|NiLuJe]]'s change of '\0' to 0: while they are both the same, keeping the syntax in terms of characters would probably be better for people to understand when dealing with strings, so I reverted the changes back. | Regarding [[User:NiLuJe|NiLuJe]]'s change of '\0' to 0: while they are both the same, keeping the syntax in terms of characters would probably be better for people to understand when dealing with strings, so I reverted the changes back. | ||
:Perhaps it should be changed to '^0'... by default we don't use \ for a backtick. This is probably what he meant to correct. -- [[User:BAILOPAN|BAILOPAN]] 18:55, 1 March 2006 (EST) | :Perhaps it should be changed to '^0'... by default we don't use \ for a backtick. This is probably what he meant to correct. -- [[User:BAILOPAN|BAILOPAN]] 18:55, 1 March 2006 (EST) | ||
+ | ::Ah, indeed, fixing that now --[[User:CyberMind|cybermind]] 02:39, 2 March 2006 (EST) | ||
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Revision as of 02:39, 2 March 2006
Regarding NiLuJe's change of '\0' to 0: while they are both the same, keeping the syntax in terms of characters would probably be better for people to understand when dealing with strings, so I reverted the changes back.
- Perhaps it should be changed to '^0'... by default we don't use \ for a backtick. This is probably what he meant to correct. -- BAILOPAN 18:55, 1 March 2006 (EST)
- Ah, indeed, fixing that now --cybermind 02:39, 2 March 2006 (EST)
Is there evidence that when something is const it's faster? I think this might be to the contrary, as the compiler has to copy it into the heap first to ensure that it isn't modified. -- BAILOPAN 00:54, 1 February 2006 (EST)
- Whether or not const variables/arrays are copied to the heap depends on the situation:
- For a function that has an array argument with a default value, the compiler allocates space for
- the default array value on the heap. However, if the array argument (with a default value) is
- also const, the pawn compiler passes the default array directly (there is no need to make a copy
- on the heap here, as the function will not attempt to change the array argument and, thereby,
- overwrite the default value).
- The arguments of a function that has "variable arguments" (denoted with the ... operator, see
- the pawn booklet "The Language") are always passed by reference. For constants and expressions
- that are not lvalues, the compiler copies the values to a cell that is allocated from the heap,
- and it passes the address of the cell to the function.
- -Page 106 (PDF page 108) of "The Implentor's Guide"
- Function insert copies in the other direction and it does not change its function argument item.
- In such a case, it is advised to mark the function argument as "const". This helps the pawn parser
- to both check for errors and to generate better (more compact, quicker) code.
- -Page 21 (PDF page 23) of "The Language Guide"
- --cybermind 01:24, 1 February 2006 (EST)
- I see, thanks for the clarification. Twilight, I'd amend your part somewhat to mirror that. -- BAILOPAN 02:54, 1 February 2006 (EST)